![(x+2) \times (4x-1,2)=0 (x+2) \times (4x-1,2)=0](https://tex.z-dn.net/?f=%28x%2B2%29+%5Ctimes+%284x-1%2C2%29%3D0)
Ответ
0
х+2=0⇒х=-2
4х-1.2=0⇒х=1.2/4=0.3