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ОПРЕДЕЛИТЕ ПРИ КАКИХ X И Y КОПЛЕКСНЫЕ ЧИСЛА z1и z2 равны.являются сопряжёнными z1= y^2+10y+xi.z2=1-i+x^2i
Ответ
2
Равны:
![y^2+10y+xi=1-i+x^2i
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\left \{ {{y^2+10y=1} \atop {x^2-1=x}} \right. \\\<br /> \left \{ {{y^2+10y-1=0} \atop {x^2-x-1=0}} \right. \\\
\left \{ {{y=-5\pm \sqrt{26} } \atop {x=1\pm \sqrt{5}}} \right.](https://tex.z-dn.net/?f=y%5E2%2B10y%2Bxi%3D1-i%2Bx%5E2i%0A%5C%5C%5C%0A+%5Cleft+%5C%7B+%7B%7By%5E2%2B10y%3D1%7D+%5Catop+%7Bx%5E2-1%3Dx%7D%7D+%5Cright.+%5C%5C%5C%3Cbr+%2F%3E%C2%A0%5Cleft+%5C%7B+%7B%7By%5E2%2B10y-1%3D0%7D+%5Catop+%7Bx%5E2-x-1%3D0%7D%7D+%5Cright.+%C2%A0%5C%5C%5C%0A+%5Cleft+%5C%7B+%7B%7By%3D-5%5Cpm+%5Csqrt%7B26%7D+%7D+%5Catop+%7Bx%3D1%5Cpm+%5Csqrt%7B5%7D%7D%7D+%5Cright.+ "y^2+10y+xi=1-i+x^2i
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\left \{ {{y^2+10y=1} \atop {x^2-1=x}} \right. \\\<br /> \left \{ {{y^2+10y-1=0} \atop {x^2-x-1=0}} \right. \\\
\left \{ {{y=-5\pm \sqrt{26} } \atop {x=1\pm \sqrt{5}}} \right.")
Сопряженные:
![y^2+10y+xi=1-i+x^2i \\\ \left \{ {{y^2+10y=1} \atop {x^2-1=-x}} \right. \\\
\left \{ {{y^2+10y-1=0} \atop {x^2+x-1=0}} \right. \\\ \left \{ {{y=-5\pm \sqrt{26} } \atop {x=-1\pm \sqrt{5}}} \right.](https://tex.z-dn.net/?f=y%5E2%2B10y%2Bxi%3D1-i%2Bx%5E2i+%5C%5C%5C+%5Cleft+%5C%7B+%7B%7By%5E2%2B10y%3D1%7D+%5Catop+%7Bx%5E2-1%3D-x%7D%7D+%5Cright.+%5C%5C%5C%0A+%5Cleft+%5C%7B+%7B%7By%5E2%2B10y-1%3D0%7D+%5Catop+%7Bx%5E2%2Bx-1%3D0%7D%7D+%5Cright.++%5C%5C%5C+%5Cleft+%5C%7B+%7B%7By%3D-5%5Cpm+%5Csqrt%7B26%7D+%7D+%5Catop+%7Bx%3D-1%5Cpm+%5Csqrt%7B5%7D%7D%7D+%5Cright.+ "y^2+10y+xi=1-i+x^2i \\\ \left \{ {{y^2+10y=1} \atop {x^2-1=-x}} \right. \\\
\left \{ {{y^2+10y-1=0} \atop {x^2+x-1=0}} \right. \\\ \left \{ {{y=-5\pm \sqrt{26} } \atop {x=-1\pm \sqrt{5}}} \right.")
Сопряженные: