56 Рассчитайте удельную энергию связи ядра атома железа 26 Fe.(mя =55,847 а.е.м.)
Ответ
17
Дано: A = 56, N = 30, Z = 26, Mя = 55.847 а.е.м., m(p) = 1.00728 а.е.м., m(n) = 1.00866 а.е.м., 1 а.е.м. = 1.66057 × 10⁻²⁷ кг
Найти: Eуд - ?
Решение:
![\boxed{E_C_B = \Delta mc^{2}} \ ; \ \boxed{E_y_d = \frac{E_C_B}{A} } \ ; \ \Delta m = Zm_p + Nm_n - M_f \\ \\ E_C_B = ((26 * 1.00728 + 30*1.00866 - 55.847) * 1.66057 * 10^{-27}) * \\ * (3*10^{8})^{2} \approx 9 *10^{-11} \ [Ds] \ = 562.5 \ [ M_\ni B] \\ \\ E_y_d = \dfrac{562.5}{56} \approx 10 \ [ \dfrac{M_\ni B}{nyklon}]](https://tex.z-dn.net/?f=%5Cboxed%7BE_C_B+%3D+%5CDelta+mc%5E%7B2%7D%7D+%5C+%3B+%5C+%5Cboxed%7BE_y_d+%3D++%5Cfrac%7BE_C_B%7D%7BA%7D+%7D+%5C+%3B+%5C+%5CDelta+m+%3D+Zm_p+%2B+Nm_n+-+M_f+%5C%5C+%5C%5C+E_C_B+%3D+%28%2826+%2A+1.00728+%2B+30%2A1.00866+-+55.847%29+%2A+1.66057+%2A+10%5E%7B-27%7D%29+%2A+%5C%5C+%2A+%283%2A10%5E%7B8%7D%29%5E%7B2%7D+%5Capprox+9+%2A10%5E%7B-11%7D+%5C+%5BDs%5D+%5C+%3D+562.5+%5C+%5B+M_%5Cni+B%5D+%5C%5C+%5C%5C+E_y_d+%3D++%5Cdfrac%7B562.5%7D%7B56%7D+%5Capprox+10+%5C+%5B+%5Cdfrac%7BM_%5Cni+B%7D%7Bnyklon%7D%5D+ "\boxed{E_C_B = \Delta mc^{2}} \ ; \ \boxed{E_y_d = \frac{E_C_B}{A} } \ ; \ \Delta m = Zm_p + Nm_n - M_f \\ \\ E_C_B = ((26 * 1.00728 + 30*1.00866 - 55.847) * 1.66057 * 10^{-27}) * \\ * (3*10^{8})^{2} \approx 9 *10^{-11} \ [Ds] \ = 562.5 \ [ M_\ni B] \\ \\ E_y_d = \dfrac{562.5}{56} \approx 10 \ [ \dfrac{M_\ni B}{nyklon}]")
Ответ: Eуд = 10 МэВ / нуклон
Найти: Eуд - ?
Решение:
Ответ: Eуд = 10 МэВ / нуклон